# How do you write #y = 4(x-3)^2+1 # in standard form?

##### 1 Answer

Jul 2, 2018

#y=4x^2-24x+37#

#### Explanation:

Given -

#y=4(x-3)^2+1#

#y=4(x^2-6x+9)+1#

#y=4x^2-24x+36+1#

#y=4x^2-24x+37#